Re: [PATCH] xrealloc: do not reuse pointer freed by zero-length realloc()

[Jeff King <peff@peff.net>]

On Tue, Sep 01, 2020 at 09:04:36AM -0400, Derrick Stolee wrote:

> > The simplest fix here is to just pass "ret" (which we know to be NULL)
> > to the follow-up realloc(). That does mean that a system which _doesn't_
> > free the original pointer would leak it. But that interpretation of the
> > standard seems unlikely (if a system didn't deallocate in this case, I'd
> > expect it to simply return the original pointer). If it turns out to be
> > an issue, we can handle the "!size" case up front instead, before we
> > call realloc() at all.
> 
> Adding an `if (!size) {free(ptr); return NULL;}` block was what I
> expected. Was that chosen just so we can rely more on the system
> realloc(), or is there a performance implication that I'm not
> seeing?

I went back and forth on whether to do that or not. This case should
basically never happen, so I like both the performance and readability
of only triggering it when realloc() returns NULL. But it would get rid
of the hand-waving above, and I doubt the performance is measurable.

If we do handle it up-front, then I think we'd actually want:

  if (!size) {
          free(ptr);
	  return xmalloc(0);
  }

(i.e., to never return NULL for consistency with xmalloc() and
xcalloc()).

> > @@ -120,7 +120,7 @@ void *xrealloc(void *ptr, size_t size)
> >  	memory_limit_check(size, 0);
> >  	ret = realloc(ptr, size);
> >  	if (!ret && !size)
> > -		ret = realloc(ptr, 1);
> > +		ret = realloc(ret, 1);
> 
> I appreciate all the additional context for such a small change.

Somebody's got to complete with you for ratio of commit message to diff
lines. :)

-Peff