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From: mame@ruby-lang.org
To: ruby-core@ruby-lang.org
Subject: [ruby-core:100379] [Ruby master Bug#17257] Integer#pow(0, 1) returns 1, which is incorrect
Date: Mon, 12 Oct 2020 04:35:01 +0000 (UTC)	[thread overview]
Message-ID: <redmine.journal-87990.20201012043501.45098@ruby-lang.org> (raw)
In-Reply-To: redmine.issue-17257.20201009141843.45098@ruby-lang.org

Issue #17257 has been updated by mame (Yusuke Endoh).


I agree that it is a bug.  The pseudocode of modular exponentiation in Wikipedia includes `if modulus = 1 then return 0` as the first check.

https://en.wikipedia.org/wiki/Modular_exponentiation#Pseudocode

I agree that there are few real use cases of modulo 1, so few one will be affected by this change.  I'll fix it soon.

```diff
diff --git a/bignum.c b/bignum.c
index 65a50ea9ba..0515e2f0d6 100644
--- a/bignum.c
+++ b/bignum.c
@@ -7136,6 +7136,7 @@ rb_int_powm(int const argc, VALUE * const argv, VALUE const num)
             long const half_val = (long)HALF_LONG_MSB;
             long const mm = FIX2LONG(m);
             if (!mm) rb_num_zerodiv();
+            if (mm == 1) return INT2FIX(0);
             if (mm <= half_val) {
                 return int_pow_tmp1(rb_int_modulo(a, m), b, mm, nega_flg);
             }
@@ -7145,6 +7146,7 @@ rb_int_powm(int const argc, VALUE * const argv, VALUE const num)
         }
         else {
             if (rb_bigzero_p(m)) rb_num_zerodiv();
+           if (bignorm(m) == INT2FIX(1)) return INT2FIX(0);
             return int_pow_tmp3(rb_int_modulo(a, m), b, m, nega_flg);
         }
     }
```

----------------------------------------
Bug #17257: Integer#pow(0, 1) returns 1, which is incorrect
https://bugs.ruby-lang.org/issues/17257#change-87990

* Author: universato (Yoshimine Sato)
* Status: Assigned
* Priority: Normal
* Assignee: mrkn (Kenta Murata)
* Backport: 2.5: UNKNOWN, 2.6: UNKNOWN, 2.7: UNKNOWN
----------------------------------------
Ruby 2.5.8, 2.6.6, 2.7.1


```ruby
p -1.pow(0, 1) #=> 1
p  0.pow(0, 1) #=> 1
p  1.pow(0, 1) #=> 1
p 1234567890.pow(0, 1) #=> 1
```

These return values should be 0.


Patch for test:

Let's add some boundary value tests to `test_pow` of [test_numeric.rb](https://github.com/ruby/ruby/blob/e014e6bf6685f681998238ff005f6d161d43ce51/test/ruby/test_numeric.rb).

```ruby
integers = [-2, -1, 0, 1, 2, 3, 6, 1234567890123456789]
integers.each do |i|
  assert_equal(0, i.pow(0, 1), '[Bug #17257]')
  assert_equal(1, i.pow(0, 2))
  assert_equal(1, i.pow(0, 3))
  assert_equal(1, i.pow(0, 6))
  assert_equal(1, i.pow(0, 1234567890123456789))
  
  assert_equal(0,  i.pow(0, -1))
  assert_equal(-1, i.pow(0, -2))
  assert_equal(-2, i.pow(0, -3))
  assert_equal(-5, i.pow(0, -6))
  assert_equal(-1234567890123456788, i.pow(0, -1234567890123456789))
end

assert_equal(0,  0.pow(2, 1))
assert_equal(0,  0.pow(3, 1))
assert_equal(0,  2.pow(3, 1))
assert_equal(0, -2.pow(3, 1))



-- 
https://bugs.ruby-lang.org/

      parent reply	other threads:[~2020-10-12  4:35 UTC|newest]

Thread overview: 13+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2020-10-09 14:18 [ruby-core:100348] [Ruby master Bug#17257] Integer#pow(0, 1) returns 1, which is incorrect universato
2020-10-10  6:54 ` [ruby-core:100355] " nobu
2020-10-10  9:18 ` [ruby-core:100356] " universato
2020-10-10 18:12 ` [ruby-core:100359] " midnight_w
2020-10-10 19:28 ` [ruby-core:100361] " marcandre-ruby-core
2020-10-11  2:48 ` [ruby-core:100363] " nobu
2020-10-11  3:32 ` [ruby-core:100365] " midnight_w
2020-10-11  3:41 ` [ruby-core:100366] " midnight_w
2020-10-11  5:54 ` [ruby-core:100367] " universato
2020-10-11 12:09 ` [ruby-core:100373] " sawadatsuyoshi
2020-10-11 13:18 ` [ruby-core:100374] " midnight_w
2020-10-11 18:46 ` [ruby-core:100375] " universato
2020-10-12  4:35 ` mame [this message]

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