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From: wishdev@gmail.com
To: ruby-core@ruby-lang.org
Subject: [ruby-core:93999] [Ruby master Feature#15811] Propsing new method for comparing equality of 2 (float) numbers relatively
Date: Mon, 29 Jul 2019 16:40:46 +0000 (UTC)	[thread overview]
Message-ID: <redmine.journal-80199.20190729164046.ed853c0ec628c3e8@ruby-lang.org> (raw)
In-Reply-To: redmine.issue-15811.20190429105809@ruby-lang.org

Issue #15811 has been updated by wishdev (John Higgins).


So there is one path that might work here (it has limits but there are limits in general that cannot be worked around).

If one takes the following scenario

We have a set of items in a store where the base unit of price is 0.01 meaning that something may cost 1.23, or 2.45, but we would not see anything like 1.234 or 45.4555 because those are lower than the working "unit of change" (0.01).

So we could construct a method like this which would allow us to determine if two items where priced within a set of "units of change"

def with_amount(item_a, item_b, within_amount, unit_of_change)
  (item_a - item_b).abs < ((within_amount).abs + (unit_of_change).abs /2)
end

So going back to earlier examples - if we take

0.01 vs 0.02 we would have a unit of change of no more than 0.01 because while we might have 0.015 as a valid option - we know that 0.03 is a valid option.

So taking the new method
item_a = 0.01
item_b = 0.02
within_amount = 0.01
unit_of_change = 0.01

(0.01 - 0.02).abs = 0.01
(0.01).abs + (0.01).abs /2 = 0.015

0.01 < 0.015 so it returns true

This works because we know that the unit of change implies the limits of the possible answers of (item_a - item_b).abs - so in this case we should have the following options

0.01, 0.02, 0.03, and so on

Since floating point subtraction is not exact we might end up with 0.0099999999994747, 0.01, or 0.010000000001 when comparing two adjacent numbers within our set

However, if we take the unit of change and halve it then we have better boundaries 0.010000000001 does not worked against a tight comparison to 0.01 but it works just fine if we compare it against 0.015 or 0.005 because those options lay well outside of the error bounds that floating point subtraction will offer us.

So the answer remains that simply comparing two numbers does not work - however, one can compare two numbers within a defined space and obtain the desired conceptual results.

The obvious rules are that within_amount must be at least equal to the unit of change. There are also issues if the within_amount is not a multiple of the unit of change. The validation check for that (checking if x is a multiple of y) starts us back down the road of inexact comparisons so it may be something that is a documented limit as opposed to a test within the method itself.

John

----------------------------------------
Feature #15811: Propsing new method for comparing equality of 2 (float) numbers relatively
https://bugs.ruby-lang.org/issues/15811#change-80199

* Author: yennguyenh (yen nguyen)
* Status: Open
* Priority: Normal
* Assignee: 
* Target version: 
----------------------------------------
# Background

Equal comparison method between 2 float numbers returns unexpected results sometimes. Therefore, a relative comparison method is needed!

# Proposal

A relative equal comparison method has been written based on a Python project! This method gives the approximation for the equal comparison based on two values: realative tolerance and absolute tolerance. Near zero value will also be considered carefully!

# Implementation

The function for that would be called close?
`close?(a, b, rel_tol, abs_tol)`

`a` and `b`: are the two values to be tested to relative closeness

`rel_tol`: is the relative tolerance -- it is the amount of error allowed, relative to the larger absolute value of a or b. For example, to set a tolerance of 5%, pass tol=0.05. The default tolerance is 1E-9, which assures that the two values are the same within about 9 decimal digits. rel_tol must be greater than 0.0

`abs_tol`: is a minimum absolute tolerance level -- useful for comparisons near zero.

# Evaluation of your implementation

By default, relative tolerance is 1E-9 which is relatively precise enough to compare two float numbers. However it can also be adjusted in case higher accuracy is requested. The absolute tolerance is by default 0.0 and need to be set in case of near-zero numbers.

# Discussion

There are some test cases available for the method which has approved the accuracy of the method. BigNumbers and integers are also tested. However, more test cases are still needed to assure even better the accuracy of the method.

# Gist 

Relative equal comparison

https://gist.github.com/yennguyenh/63d5e7a11f354f796b43ada037c4b2c5

Test cases

https://gist.github.com/yennguyenh/2e81dc72b310cb9d886a82faf3d536ef



-- 
https://bugs.ruby-lang.org/

      parent reply	other threads:[~2019-07-29 16:40 UTC|newest]

Thread overview: 16+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
     [not found] <redmine.issue-15811.20190429105809@ruby-lang.org>
2019-04-29 10:58 ` [ruby-core:92475] [Ruby trunk Feature#15811] Propsing new method for comparing equality of 2 (float) numbers relatively hai-yen.nguyen
2019-04-29 11:03 ` [ruby-core:92476] " hai-yen.nguyen
2019-04-29 11:35 ` [ruby-core:92477] " manga.osyo
2019-04-29 11:55 ` [ruby-core:92478] " shevegen
2019-04-29 14:55 ` [ruby-core:92479] " wishdev
2019-04-30  7:23 ` [ruby-core:92488] " nobu
2019-04-30  8:16 ` [ruby-core:92489] " duerst
2019-04-30 10:50 ` [ruby-core:92491] " sawadatsuyoshi
2019-04-30 13:29 ` [ruby-core:92494] " nobu
2019-05-09  8:09 ` [ruby-core:92612] " hai-yen.nguyen
2019-05-09 10:22 ` [ruby-core:92613] " hai-yen.nguyen
2019-07-29  6:54 ` [ruby-core:93966] [Ruby master " ko1
2019-07-29  7:34 ` [ruby-core:93975] " wishdev
2019-07-29  7:35 ` [ruby-core:93976] " muraken
2019-07-29  7:49 ` [ruby-core:93981] " wishdev
2019-07-29 16:40 ` wishdev [this message]

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