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* [ruby-core:99553] [Ruby master Bug#17113] /\K/ in separator for String#split behaves differently than /(?<=)/
@ 2020-08-11  9:59 kasumi
  2020-08-11 10:03 ` [ruby-core:99554] " kasumi
  0 siblings, 1 reply; 2+ messages in thread
From: kasumi @ 2020-08-11  9:59 UTC (permalink / raw)
  To: ruby-core

Issue #17113 has been reported by hanazuki (Kasumi Hanazuki).

----------------------------------------
Bug #17113: /\K/ in separator for String#split behaves differently than /(?<=)/
https://bugs.ruby-lang.org/issues/17113

* Author: hanazuki (Kasumi Hanazuki)
* Status: Open
* Priority: Normal
* ruby -v: ruby 2.8.0dev (2020-08-11T07:51:07Z master 5af983af4f) [x86_64-linux]
* Backport: 2.5: UNKNOWN, 2.6: UNKNOWN, 2.7: UNKNOWN
----------------------------------------
When a String is `#split`ted with a pattern containing /\K/ (lookbehind) operator,
the portion that matches the lookbehind pattern will not appear in the result.

```ruby
"abcd".split(/b\Kc/)  # => ["a", "d"]
"abcd".split(/(?<=b)c/)  # => ["ab", "d"] -- expected result
```

In this example, since `/b\Kc/` matches `"c"` in `"abcd"`, the result is expected to be `["ab", "d"]`. Actually `["a", "d"]` is returned.
`(?<=)` operator seems to work expectedly.





-- 
https://bugs.ruby-lang.org/

^ permalink raw reply	[flat|nested] 2+ messages in thread

* [ruby-core:99554] [Ruby master Bug#17113] /\K/ in separator for String#split behaves differently than /(?<=)/
  2020-08-11  9:59 [ruby-core:99553] [Ruby master Bug#17113] /\K/ in separator for String#split behaves differently than /(?<=)/ kasumi
@ 2020-08-11 10:03 ` kasumi
  0 siblings, 0 replies; 2+ messages in thread
From: kasumi @ 2020-08-11 10:03 UTC (permalink / raw)
  To: ruby-core

Issue #17113 has been updated by hanazuki (Kasumi Hanazuki).


Patch: https://github.com/ruby/ruby/pull/3407

----------------------------------------
Bug #17113: /\K/ in separator for String#split behaves differently than /(?<=)/
https://bugs.ruby-lang.org/issues/17113#change-87015

* Author: hanazuki (Kasumi Hanazuki)
* Status: Open
* Priority: Normal
* ruby -v: ruby 2.8.0dev (2020-08-11T07:51:07Z master 5af983af4f) [x86_64-linux]
* Backport: 2.5: UNKNOWN, 2.6: UNKNOWN, 2.7: UNKNOWN
----------------------------------------
When a String is `#split`ted with a pattern containing /\K/ (lookbehind) operator,
the portion that matches the lookbehind pattern will not appear in the result.

```ruby
"abcd".split(/b\Kc/)  # => ["a", "d"]
"abcd".split(/(?<=b)c/)  # => ["ab", "d"] -- expected result
```

In this example, since `/b\Kc/` matches `"c"` in `"abcd"`, the result is expected to be `["ab", "d"]`. Actually `["a", "d"]` is returned.
`(?<=)` operator seems to work expectedly.





-- 
https://bugs.ruby-lang.org/

^ permalink raw reply	[flat|nested] 2+ messages in thread

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