Re: List all commits of a specified file in oldest to newest order

[Jeff King <peff@peff.net>]

On Fri, Nov 05, 2021 at 11:49:03AM -0700, Junio C Hamano wrote:

> Jeff King <peff@peff.net> writes:
> 
> > As a workaround, you can get what you want by two separate traversals:
> > one to collect the commits via --follow, and then another to actually
> > show them (but without doing any further walking). Like:
> >
> >   git log --follow --format=%H -- $your_file |
> >   git log --stdin --no-walk --reverse [--oneline, -p, etc]
> 
> We learn new things every day.
> 
> Knowing the implementation, it is sort of obvious (we push the
> objects into the pending list, populate the revs.commits in
> prepare_revision_walk() from the pending list in order,
> get_revision() first reverses the revs.commits and then gives out
> the elements), but I didn't know the combination of "--no-walk" and
> "--reverse" did something sensible ;-)

I admit that I did not know if it would work either until I tried it
earlier today. ;)

-Peff