Re: [PATCH] worktree: add: introduce the --name option

[Duy Nguyen <pclouds@gmail.com>]

On Tue, Jul 19, 2016 at 9:35 PM, Antoine Tenart <antoine.tenart@ack.tf> wrote:
> On Tue, Jul 19, 2016 at 09:04:11PM +0200, Duy Nguyen wrote:
>> On Tue, Jul 19, 2016 at 8:54 PM, Antoine Tenart <antoine.tenart@ack.tf> wrote:
>> > On Tue, Jul 19, 2016 at 08:23:58PM +0200, Duy Nguyen wrote:
>> >> On Tue, Jul 19, 2016 at 8:04 PM, Junio C Hamano <gitster@pobox.com> wrote:
>> >>
>> >> 080739b (worktree.c: find_worktree() search by path suffix -
>> >> 2016-06-13) from 'next' should help identify worktrees in this case by
>> >> specifying 'project0/foo', 'project1/foo'... Granted it's not fun to
>> >> type all that when 'project0/foo' is something long, and bash
>> >> completion probably does not help much either.
>> >
>> > So with this I'll be able to create new worktrees, using paths having
>> > the same basename, but in different let's say "project directories"?
>>
>> Well, internal name is still out of your control, but if you want to
>> do something to a worktree you can say "do project0/foo". With 'next'
>> those verbs can be lock and unlock. We probably can make 'worktree
>> list' take filter and show just one worktree (and just add "git
>> worktree show" for that).
>
> Hmm, so if I understand correctly my use case still won't be supported,
> as adding a new worktree with the same basename will fail. Or did I miss
> something?

Hm... _what_ fails? If you create two worktrees project0/foo and
project1/foo, you'll get .git/worktrees/foo and .git/worktrees/foo1
but worktree creation should succeed both times. As long as you don't
have to look into .git/worktrees/ everything should be fine, you won't
see foo vs foo1.

If you absolutely have to, I'm thinking of "git --rev-parse
--worktree=<xxx> --git-dir" (or something similar) that will give you
$GIT_DIR to a specific worktree (e.g. .git/worktrees/foo or
.git/worktrees/foo1). Then you can specify "git rev-parse
--worktree=project0/foo --git-dir" and still don't have to see foo vs
foo1.
-- 
Duy