Re: t1450-fsck (sometimes/often) failes on Mac OS X

[Junio C Hamano <gitster@pobox.com>]

Torsten Bögershausen <tboegi@web.de> writes:

> With help of Junio's comments I probably found the reason why the test
> behaves differently:
>
> The objects are checked in a certain order, based on the inode number.
>
> Which seems to be the same on most machines: when files are created
> in a certain order, then the inode numbers are in the same order.
>
> When the inode numbering changes for reasons known to the file system,
> the order changes and fsck takes a different code path.
>
> To provoke the error, the following helped at my Linux box:
>
> diff --git a/builtin/fsck.c b/builtin/fsck.c
> index a710227..bba8082 100644
> --- a/builtin/fsck.c
> +++ b/builtin/fsck.c
> @@ -373,7 +373,7 @@ static struct {
>
>  static int ino_compare(const void *_a, const void *_b)
>  {
> -       const struct sha1_entry *a = _a, *b = _b;
> +       const struct sha1_entry *a = _b, *b = _a;
>         unsigned long ino1 = a->ino, ino2 = b->ino;
>         return ino1 < ino2 ? -1 : ino1 > ino2 ? 1 : 0;
>  }
>
> The bad news: I haven't found the time to prepare a fix.

Thanks for a reproduction. Yes, the test t1450.13 is expecting too
much.

If it finds the $sha blob first and then looks at $tag tag, then it
will notice that the tag is pointing at a blob but claims it must be
a commit.  If it finds the $tag tag first, it will remember that the
tag claimed $sha must be a commit, and when later it sees $sha, it
finds that it is not of the type it is expecting (namely, a commit),
and says "the object called $sha is broken".

So "test_must_fail git fsck --tags" is correct.  The fsck must find
the breakage either way.

The last piece to expect "error in tag.*broken links" in the output
is wrong.  Probably we should remove the misguided check and end
it with "test_must_fail git fsck --tags".